Buffalo N.Y. (WGR 550) - Buffalo Bills cornerback Rasul Douglas has been named the AFC Defensive Player of the Week for his performance this past Sunday against the New England Patriots in Week 17.
Douglas helped the Bills in a huge way defensively, starting with the very first defensive snap with a pass break up that led to an interception by defensive tackle Ed Oliver. His other two passes defended resulted in interceptions of his own, one of which being returned 40 yards for a touchdown.
The 28-year-old was acquired at the NFL Trade Deadline by the Bills from the Green Bay Packers, and has become an integral part of the Buffalo secondary. In eight games with the Bills this season, Douglas has registered 29 total tackles, one tackle for loss, a sack, four interceptions and two fumble recoveries.
Douglas became the first Bills defender with two interceptions and an interception returned for a touchdown in a single game since Nickell Robey-Coleman did so against the Los Angeles Rams back in 2016.
This is the second time Douglas has received the honor in his NFL career, and the first Bills cornerback to earn AFC Defensive Player of the Week since Tre'Davious White in 2019.
Douglas is the second Bills defender to win AFC Defensive Player of the Week honors this season, joining linebacker Terrel Bernard for his Week 3 performance against the Washington Commanders.
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Overall, Douglas is the fifth Bills player this season to win AFC Player of the Week honors, joining quarterback Josh Allen (twice), Bernard, special teamer Reggie Gilliam and running back James Cook.
