Tremaine Edmunds named AFC Defensive Player of the Week

Edmunds had a big day this past Sunday against the Texans
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Buffalo Bills linebacker Tremaine Edmunds has been named the AFC Defensive Player of the Week following his Week 4 performance against the Houston Texans this past Sunday at Highmark Stadium in Orchard Park.

In Buffalo's 40-0 win over the Texans, Edmunds led the Bills with six total tackles, while also adding a defended pass and an interception to his stat line.

It is the first time in Edmunds' career that he has been named the AFC Defensive Player of the Week. He is the first Bills defensive player to earn the weekly honor from the National Football League since linebacker A.J. Klein in Week 12 last season against the Los Angeles Chargers.

Edmunds has been a huge piece to the success for the Buffalo defense through four games this season. The 23-year-old has compiled 21 tackles so far this season, while also picking up a tackle for a loss, two passes defended and his interception in Week 4.

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Through the first four games of the 2021 campaign, the Bills have the top-ranked defense in the entire NFL, allowing just 867 total yards, which is an average of just 216.8 yards-against per-game. In addition, the Bills are only allowing their opposition an average of 11 points per-game, which is also a league-best mark.

One large reasoning behind the unit's overall success has been its ability to force turnovers once again. The Bills lead the NFL with 11 takeaways through four games, which includes seven interceptions and four fumbles.

Edmunds becomes the second Bills player this season to earn AFC Player of the Week honors. Josh Allen earned AFC Offensive Player of the Week honors for his performance in Buffalo's Week 3 win over the Washington Football Team.